汽车理论习题1.3答案（MATLAB程序源代码）

xiaopiujy

驱动力：
n=600:4000;
Tq=-19.313+295.27*(n/1000)-165.44*(n/1000).^2+40.874*(n/1000).^3-3.8445*(n/1000).^4;
f1=Tq*6.09*5.83*0.85/0.367;
f2=Tq*3.09*5.83*0.85/0.367;
f3=Tq*1.71*5.83*0.85/0.367;
f4=Tq*5.83*0.85/0.367;
ua=0.337*0.367*n/5.83;
u1=ua/6.09;
u2=ua/3.09;
u3=ua/1.71;
u4=ua/1;
ff=3880*9.8*0.013;
ft1=ff+2.77/21.15*u1.^2;
ft2=ff+2.77/21.15*u2.^2;
ft3=ff+2.77/21.15*u3.^2;
ft4=ff+2.77/21.15*u4.^2;
plot(u1,f1,u2,f2,u3,f3,u4,f4,u1,ft1,u2,ft2,u3,ft3,u4,ft4,u1,ff,u2,ff,u3,ff,u4,ff)
加速度倒数曲线：
n=600:4000;
Tq=-19.313+295.27*(n/1000)-165.44*(n/1000).^2+40.874*(n/1000).^3-3.8445*(n/1000).^4;
f1=Tq*6.09*5.83*0.85/0.367;
f2=Tq*3.09*5.83*0.85/0.367;
f3=Tq*1.71*5.83*0.85/0.367;
f4=Tq*5.83*0.85/0.367;
e=1+(1.798+3.598)/(3880*0.367.^2);
r=0.218*5.83.^2*0.85/(3880*0.367.^2);
q1=e+r*6.09.^2;
q2=e+r*3.09.^2;
q3=e+r*1.71.^2;
q4=e+r;
ua=0.337*0.367*n/5.83;
u1=ua/6.09;
u2=ua/3.09;
u3=ua/1.71;
u4=ua/1;
ff=3880*9.8*0.013;
ft1=ff+2.77/21.15*u1.^2;
ft2=ff+2.77/21.15*u2.^2;
ft3=ff+2.77/21.15*u3.^2;
ft4=ff+2.77/21.15*u4.^2;
a1=(f1-ft1)/(q1*3880);
a2=(f2-ft2)/(q2*3880);
a3=(f3-ft3)/(q3*3880);
a4=(f4-ft4)/(q4*3880);
a11=1./a1;
a22=1./a2;
a33=1./a3;
a44=1./a4;
plot(u1,a11,u2,a22,u3,a33,u4,a44)

easyszp@126.com

你太狠啦！，希望有时间指点小弟一下

邓郎

貌似你这个答案不全吧

zhai8906

学习了！